亚洲日韩欧美一区二区三区在线_国产亚洲日韩欧美另类丝瓜APP_欧美日本中文字幕_性XXXX欧美老妇506070

代寫COMP528、代做c/c++,Python程序語言

時間:2024-07-27  來源:  作者: 我要糾錯



University of Liverpool Assignment 1 Resit COMP528
In this assignment, you are asked to implement 2 algorithms for the Travelling Salesman
Problem. This document explains the operations in detail, so you do not need previous
knowledge. You are encouraged to begin work on this as soon as possible to avoid the queue
times on Barkla closer to the deadline. We would be happy to clarify anything you do not
understand in this report.
1 The Travelling Salesman Problem (TSP)
The travelling salesman problem is a problem that seeks to answer the following question:
‘Given a list of vertices and the distances between each pair of vertices, what is the shortest
possible route that visits each vertex exactly once and returns to the origin vertex?’.
(a) A fully connected graph
(b) The shortest route around all vertices
Figure 1: An example of the travelling salesman problem
The travelling salesman problem is an NP-hard problem, that meaning an exact solution
cannot be solved in polynomial time. However, there are polynomial solutions that can
be used which give an approximation of the shortest route between all vertices. In this
assignment you are asked to implement 2 of these.
1.1 Terminology
We will call each point on the graph the vertex. There are 6 vertices in Figure 1.
We will call each connection between vertices the edge. There are 15 edges in Figure 1.
We will call two vertices connected if they have an edge between them.
The sequence of vertices that are visited is called the tour. The tour for Figure 1(b) is
(0, 2, 4, 5, 3, 1, 0). Note the tour always starts and ends at the origin vertex.
A partial tour is a tour that has not yet visited all the vertices.
2023-2024 1University of Liverpool Assignment 1 Resit COMP528
2 The solutions
2.1 Preparation of Solution
You are given a number of coordinate ffles with this format:
x, y
4.81263062736921, 8.34719930253777
2.90156816804616, 0.39593575612759
1.13649642931556, 2.27359458630845
4.49079099682118, 2.97491204443206
9.84251616851393, 9.10783427307047
Figure 2: Format of a coord ffle
Each line is a coordinate for a vertex, with the x and y coordinate being separated by a
comma. You will need to convert this into a distance matrix.
0.000000 8.177698 7.099481 5.381919 5.087073
8.177698 0.000000 2.577029 3.029315 11.138848
7.099481 2.577029 0.000000 3.426826 11.068045
5.381919 3.029315 3.426826 0.000000 8.139637
5.087073 11.138848 11.068045 8.139637 0.000000
Figure 3: A distance matrix for Figure 2
To convert the coordinates to a distance matrix, you will need make use of the euclidean
distance formula.
d =
p
(xi − xj )
2 + (yi − yj )
2
Figure 4: The euclidean distance formula
Where: d is the distance between 2 vertices vi and vj
, xi and yi are the coordinates of the
vertex vi
, and xj and yj are the coordinates of the vertex vj
.
2023-2024 2University of Liverpool Assignment 1 Resit COMP528
2.2 Smallest Sum Insertion
The smallest sum insertion algorithm starts the tour with the vertex with the lowest index.
In this case that is vertex 0. Each step, it selects a currently unvisited vertex where the
total edge cost to all the vertices in the partial tour is minimal. It then inserts it between
two connected vertices in the partial tour where the cost of inserting it between those two
connected vertices is minimal.
These steps can be followed to implement the smallest sum insertion algorithm. Assume
that the indices i, j, k etc; are vertex labels unless stated otherwise. In a tiebreak situation,
always pick the lowest index(indices).
1. Start off with a vertex vi.
4
Figure 5: Step 1 of Smallest Sum Insertion
2. Find a vertex vj such that
Pt=Length(partialtour)
t=0
dist(vt
, vj ) is minimal.
Figure 6: Step 2 of Smallest Sum Insertion
3. Insert vj between two connected vertices in the partial tour vn and vn+1, where n is a
position in the partial tour, such that dist(vn, vj ) + dist(vn+1, vj ) - dist(vn, vn+1) is
minimal.
4. Repeat steps 2 and 3 until all of the vertices have been visited.
2023-2024 3University of Liverpool Assignment 1 Resit COMP528
Figure 7: Step 3 of Smallest Sum Insertion
4
(a) Select the vertex
(b) Insert the vertex
Figure 8: Step 4 of Smallest Sum Insertion
(b) Insert the vertex
Figure 9: Step 5 of Smallest Sum Insertion
2023-2024 4University of Liverpool Assignment 1 Resit COMP528
4
(b) Insert the vertex
Figure 10: Step 6 of Smallest Sum Insertion
(a) Select the vertex
(b) Insert the vertex
Figure 11: Step 7 of Smallest Sum Insertion
2023-2024 5University of Liverpool Assignment 1 Resit COMP528
2.3 MinMax Insertion
The minmax insertion algorithm starts the tour with the vertex with the lowest index. In this
case that is vertex 0. Each step, it selects a currently unvisited vertex where the largest edge
to a vertex in the partial tour is minimal. It then inserts it between two connected vertices
in the partial tour where the cost of inserting it between those two connected vertices is
minimal.
These steps can be followed to implement the minmax insertion algorithm. Assume that the
indices i, j, k etc; are vertex labels unless stated otherwise. In a tiebreak situation, always
pick the lowest index(indices).
1. Start off with a vertex vi.
Figure 12: Step 1 of Minmax Insertion
2. Find a vertex vj such that M ax(dist(vt
, vj )) is minimal, where t is the list of elements
in the tour.
Figure 13: Step 2 of Minmax Insertion
3. Insert vj between two connected vertices in the partial tour vn and vn+1, where n is a
position in the partial tour, such that dist(vn, vj ) + dist(vn+1, vj ) - dist(vn, vn+1) is
minimal.
4. Repeat steps 2 and 3 until all of the vertices have been visited.
2023-2024 6University of Liverpool Assignment 1 Resit COMP528
Figure 14: Step 3 of Minmax Insertion
(a) Select the vertex
4
(b) Insert the vertex
Figure 15: Step 4 of Minmax Insertion
(a) Select the vertex
(b) Insert the vertex
Figure 16: Step 5 of Minmax Insertion
2023-2024 7University of Liverpool Assignment 1 Resit COMP528
(a) Select the vertex
4
(b) Insert the vertex
Figure 17: Step 6 of Minmax Insertion
(b) Insert the vertex
Figure 18: Step 7 of Minmax Insertion
2023-2024 8University of Liverpool Assignment 1 Resit COMP528
3 Running your programs
Your program should be able to be ran like so:
$ ./<program name >. exe <c o o r d i n a t e f i l e n a m e > <o u t p u t fil e n am e >
Therefore, your program should accept a coordinate file, and an output file as arguments.
Note that C considers the first argument as the program executable. Both implementations
should read a coordinate file, run either smallest sum insertion or MinMax insertion, and
write the tour to the output file.
3.1 Provided Code
You are provided with the file coordReader.c, which you will need to include this file when
compiling your programs.
1. readNumOfCoords(): This function takes a filename as a parameter and returns the
number of coordinates in the given file as an integer.
2. readCoords(): This function takes the filename and the number of coordinates as
parameters, and returns the coordinates from a file and stores it in a two-dimensional
array of doubles, where coords[i][0] is the x coordinate for the ith coordinate, and
coords[i][1] is the y coordinate for the ith coordinate.
3. writeTourToFile(): This function takes the tour, the tour length, and the output
filename as parameters, and writes the tour to the given file.
4 Instructions
• Implement a serial solution for the smallest sum insertion and the MinMax insertion.
Name these: ssInsertion.c, mmInsertion.c.
• Implement a parallel solution, using OpenMP,for the smallest sum insertion and the
MinMax insertion algorithms. Name these: ompssInsertion.c, ompmmInsertion.c.
• Create a Makefile and call it ”Makefile” which performs as the list states below. Without
the Makefile, your code will not grade on CodeGrade.
– make ssi compiles ssInsertion.c and coordReader.c into ssi.exe with the GNU
compiler
– make mmi compiles mmInsertion.c and coordReader.c into mmi.exe with the
GNU compiler
2023-2024 9University of Liverpool Assignment 1 Resit COMP528
– make ssomp compiles ompssInsertion.c and coordReader.c into ssomp.exe with
the GNU compiler
– make mmomp compiles ompmmInsertion.c and coordReader.c into mmomp.exe
with the GNU compiler
– make issomp compiles ompssInsertion.c and coordReader.c into issomp.exe with
the Intel compiler
– make immomp compiles ompmmInsertion.c and coordReader.c into immomp.exe
the Intel compiler
• Test each of your parallel solutions using 1, 2, 4, 8, 16, and 32 threads, recording
the time it takes to solve each one. Record the start time after you read from the
coordinates file, and the end time before you write to the output file. Do all testing
with the large data file.
• Plot a speedup plot with the speedup on the y-axis and the number of threads on the
x-axis for each parallel solution.
• Plot a parallel efficiency plot with parallel efficiency on the y-axis and the number of
threads on the x-axis for each parallel solution.
• Write a report that, for each solution, using no more than 1 page per solution,
describes: your serial version, and your parallelisation strategy.
• In your report, include: the speedup and parallel efficiency plots, how you conducted
each measurement and calculation to plot these, and screenshots of you compiling and
running your program. These do not contribute to the page limit.
• Your final submission should be uploaded onto CodeGrade. The files you
upload should be:
1. Makefile
2. ssInsertion.c
3. mmInsertion.c
4. ompssInsertion.c
5. ompmmInsertion.c
6. report.pdf
7. The slurm script you used to run your code on Barkla.
2023-2024 10University of Liverpool Assignment 1 Resit COMP528
5 Hints
You can also parallelise the conversion of the coordinates to the distance matrix. When
declaring arrays, it’s better to use dynamic memory allocation. You can do this by:
int ∗ o n e d a r ra y = ( int ∗) malloc ( numOfElements ∗ s i z e o f ( int ) ) ;
For a 2-D array:
int ∗∗ twod a r ra y = ( int ∗∗) malloc ( numOfElements ∗ s i z e o f ( int ∗ ) ) ;
for ( int i = 0 ; i < numOfElements ; i ++){
twod a r ra y [ i ] = ( int ∗) malloc ( numOfElements ∗ s i z e o f ( int ) ) ;
}
5.1 MakeFile
You are instructed to use a MakeFile to compile the code in any way you like. An example
of how to use a MakeFile can be used here:
{make command } : { t a r g e t f i l e s }
{compile command}
s s i : s s I n s e r t i o n . c coordReader . c
gcc s s I n s e r t i o n . c coordReader . c −o s s i . exe −lm
Now, on the command line, if you type ‘make ssi‘, the compile command is automatically
executed. It is worth noting, the compile command must be indented. The target files are
the files that must be present for the make command to execute.
This command may work for you and it may not. The point is to allow you to compile
however you like. If you want to declare the iterator in a for loop, you would have to add the
compiler flag −std=c99. −fopenmp is for the GNU compiler and −qopenmp is for the
Intel Compiler. If you find that the MakeFile is not working, please get in contact as soon
as possible.
Contact: h.j.forbes@liverpool.ac.uk
2023-2024 11University of Liverpool Assignment 1 Resit COMP528
6 Marking scheme
1 Code that compiles without errors or warnings 15%
2 Same numerical results for test cases (tested on CodeGrade) 20%
3 Speedup plot 10%
4 Parallel Efficiency Plot 10%
5 Parallel efficiency up to 32 threads (tests on Barkla yields good efficiency
for 1 Rank with 1, 2, 4, 8, 16, 32 OMP threads)
15%
6 Speed of program (tests on Barkla yields good runtime for 1, 2, 4, 8, 16,
32 ranks with 1 OMP thread)
10%
7 Clean code and comments 10%
8 Report 10%
Table 1: Marking scheme
The purpose of this assessment is to develop your skills in analysing numerical programs and
developing parallel programs using OpenMP. This assessment accounts for 40% of your final
mark, however as it is a resit you will be capped at 50% unless otherwise stated by the Student
Experience Team. Your work will be submitted to automatic plagiarism/collusion detection
systems, and those exceeding a threshold will be reported to the Academic Integrity Officer for
investigation regarding adhesion to the university’s policy https://www.liverpool.ac.uk/
media/livacuk/tqsd/code-of-practice-on-assessment/appendix_L_cop_assess.pdf.
7 Deadline
The deadline is 23:59 GMT Friday the 2nd of August 2024. https://www.liverp
ool.ac.uk/aqsd/academic-codes-of-practice/code-of-practice-on-assessment/
2023-2024 12

請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp




 

標簽:

掃一掃在手機打開當前頁
  • 上一篇:CIT 593代做、代寫Java/c++語言編程
  • 下一篇:代寫COMP4337、代做Python編程設計
  • 代做IERG 4080、代寫Python程序語言
  • CS202代做、代寫Java/Python程序語言
  • 代做SEHH2239、Python程序語言代寫
  • COMP3334代做、代寫Python程序語言
  • 代寫COMP9021、代做Python程序語言
  • 昆明生活資訊

    昆明圖文信息
    蝴蝶泉(4A)-大理旅游
    蝴蝶泉(4A)-大理旅游
    油炸竹蟲
    油炸竹蟲
    酸筍煮魚(雞)
    酸筍煮魚(雞)
    竹筒飯
    竹筒飯
    香茅草烤魚
    香茅草烤魚
    檸檬烤魚
    檸檬烤魚
    昆明西山國家級風景名勝區(qū)
    昆明西山國家級風景名勝區(qū)
    昆明旅游索道攻略
    昆明旅游索道攻略
  • NBA直播 短信驗證碼平臺 幣安官網(wǎng)下載 歐冠直播 WPS下載

    關于我們 | 打賞支持 | 廣告服務 | 聯(lián)系我們 | 網(wǎng)站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 kmw.cc Inc. All Rights Reserved. 昆明網(wǎng) 版權所有
    ICP備06013414號-3 公安備 42010502001045

    亚洲日韩欧美一区二区三区在线_国产亚洲日韩欧美另类丝瓜APP_欧美日本中文字幕_性XXXX欧美老妇506070

        色一情一乱一乱一91av| 中文字幕一区不卡| 亚洲综合色婷婷| 91在线视频免费91| 国产日韩欧美精品综合| 久久精品国产久精国产| 欧美一区日韩一区| 日本不卡视频在线观看| 3d动漫精品啪啪1区2区免费| 亚洲狠狠爱一区二区三区| 色综合天天性综合| 亚洲人成网站精品片在线观看| 国产69精品久久久久777| 亚洲精品在线一区二区| 日本不卡123| 在线不卡中文字幕| 亚洲精品高清在线| av一区二区久久| 国产欧美一区二区在线| 自拍av一区二区三区| 日本亚洲三级在线| 91小宝寻花一区二区三区| 精品免费日韩av| 午夜影院久久久| 91在线丨porny丨国产| 亚洲日本在线天堂| 91免费视频网址| 国产三级一区二区三区| 国产一区二区电影| 久久综合九色综合97_久久久| 日韩电影在线观看网站| 日韩三级在线免费观看| 日韩成人av影视| 欧美一区二区视频网站| 日韩福利电影在线| 欧美一区二区三区喷汁尤物| 亚洲精品视频在线看| 色婷婷av一区二区三区软件| 自拍偷拍亚洲欧美日韩| 国产综合久久久久久鬼色| 制服丝袜中文字幕亚洲| 亚洲成人av一区二区| 日韩精品在线看片z| 久久99热这里只有精品| 精品国产乱子伦一区| 国产伦精品一区二区三区免费 | 奇米影视在线99精品| 欧美一区二区视频在线观看2020| 日本成人在线电影网| 精品国产乱子伦一区| 国产一级精品在线| 欧美成人精品3d动漫h| 麻豆91精品91久久久的内涵| 国产欧美中文在线| 91浏览器入口在线观看| 亚洲成人激情社区| 精品国产乱码久久久久久蜜臀| 国产精品综合av一区二区国产馆| 国产精品青草久久| 欧美无人高清视频在线观看| 奇米影视7777精品一区二区| 久久精品亚洲乱码伦伦中文| 91在线免费播放| 日韩av中文字幕一区二区三区 | 欧美韩国日本不卡| aa级大片欧美| 亚洲一区av在线| 欧美激情在线一区二区三区| 欧美亚洲免费在线一区| 九九视频精品免费| 亚洲三级视频在线观看| 日韩写真欧美这视频| 99久久免费精品| 日韩高清一区在线| 国产精品欧美一区喷水| 欧美美女黄视频| 成人国产亚洲欧美成人综合网| 亚洲bt欧美bt精品777| 国产亚洲成aⅴ人片在线观看| 大桥未久av一区二区三区中文| 亚洲国产另类av| 中文字幕第一区综合| 91精品国产综合久久久蜜臀粉嫩| www.成人网.com| 久久不见久久见免费视频7| 一区二区三区资源| 国产欧美日韩视频在线观看| 欧美吞精做爰啪啪高潮| 成人h动漫精品| 国产一区不卡精品| 日日嗨av一区二区三区四区| 久久综合久久综合久久综合| 日本乱码高清不卡字幕| 国产伦精一区二区三区| 日韩成人dvd| 亚洲福利视频三区| 亚洲欧美日韩精品久久久久| 国产色综合久久| 日韩午夜av电影| 在线观看亚洲一区| eeuss鲁片一区二区三区在线看| 美女mm1313爽爽久久久蜜臀| 亚洲图片欧美色图| 亚洲黄色在线视频| 亚洲欧洲精品一区二区三区不卡| 国产亚洲污的网站| 精品国产成人在线影院| 日韩欧美黄色影院| 欧美丰满一区二区免费视频| 在线视频欧美精品| 韩国女主播一区| 日韩成人av影视| 国产精品一区二区久久精品爱涩| 麻豆精品精品国产自在97香蕉| 日韩高清国产一区在线| 调教+趴+乳夹+国产+精品| 午夜精品一区二区三区三上悠亚| 亚洲黄网站在线观看| 亚洲女爱视频在线| 一区二区三区不卡在线观看 | 精品日韩成人av| 精品粉嫩超白一线天av| 久久久综合精品| 国产偷v国产偷v亚洲高清| 国产三级一区二区三区| 国产午夜精品理论片a级大结局| 国产人久久人人人人爽| 国产亚洲精品福利| 中文一区在线播放| 亚洲色图.com| 亚洲欧洲精品天堂一级 | 美女任你摸久久 | 成人高清视频在线| 99精品视频中文字幕| 色婷婷国产精品| 精品视频1区2区| 日韩你懂的在线观看| 国产丝袜在线精品| 伊人一区二区三区| 日日夜夜精品视频免费| 久久国产剧场电影| 国产成人精品亚洲日本在线桃色| 国产成人综合在线观看| 91丨porny丨国产入口| 在线免费观看日韩欧美| 在线观看亚洲精品| 欧美理论在线播放| 欧美电视剧免费观看| 2020国产成人综合网| 中文字幕综合网| 青青国产91久久久久久| 国产福利一区在线| 色婷婷av久久久久久久| 欧美一级国产精品| 亚洲国产成人午夜在线一区| 亚洲一区二区欧美激情| 欧美a一区二区| 国产一区二区三区电影在线观看 | 91亚洲大成网污www| 91精品国产综合久久久久久漫画| 久久这里只有精品6| 一区二区三区精品视频在线| 免费成人在线观看视频| 成人国产亚洲欧美成人综合网| 欧美日韩一卡二卡三卡| 国产欧美日韩视频在线观看| 亚洲成人免费av| 成人激情动漫在线观看| 色哟哟一区二区三区| 欧美一区二区三区播放老司机| 久久蜜桃一区二区| 亚洲综合视频网| 岛国av在线一区| 欧美一区二区三区小说| 亚洲丝袜精品丝袜在线| 国产综合色精品一区二区三区| 在线观看日韩一区| 中文字幕av不卡| 极品销魂美女一区二区三区| 精品婷婷伊人一区三区三| 国产精品萝li| 国产经典欧美精品| 日韩亚洲欧美在线| 亚洲国产另类av| 色综合久久久久久久久久久| 欧美xxx久久| 极品少妇xxxx偷拍精品少妇| 欧美人伦禁忌dvd放荡欲情| 中文字幕欧美一区| 国产电影一区在线| 久久伊99综合婷婷久久伊| 日本欧美一区二区| 777xxx欧美| 亚洲成av人片一区二区三区| 在线免费不卡视频| 一区二区三区影院| 在线观看亚洲专区| 一个色综合网站| 欧亚洲嫩模精品一区三区| 亚洲女人****多毛耸耸8|